Introduction & Context
Azeotrope identification is a critical task in process engineering, particularly in the design and optimization of distillation columns. An azeotrope is a liquid mixture that exhibits a constant boiling point and produces a vapor phase with the same composition as the liquid phase. Because the relative volatility of the components becomes unity at this point, conventional distillation cannot separate the mixture beyond the azeotropic composition. Understanding these points is essential for determining the feasibility of separation processes, selecting appropriate entrainers for extractive distillation, or designing pressure-swing distillation systems.
Methodology & Formulas
The characterization of an azeotrope relies on the conversion of mass-based compositions to molar-based compositions and the evaluation of the thermodynamic equilibrium state. The following formulas define the transformation and identification logic:
First, the weight fraction wi is converted to the mole fraction xi using the molecular weights Mi of the components:
\[ x_{A} = \frac{\frac{w_{A}}{M_{A}}}{\frac{w_{A}}{M_{A}} + \frac{w_{B}}{M_{B}}} \]
The total mole fraction must satisfy the closure condition:
\[ x_{A} + x_{B} = 1 \]
The identification of the azeotropic point is confirmed by the relative volatility αAB, which represents the ratio of the distribution coefficients of the two components. At the azeotropic point, the vapor composition yi equals the liquid composition xi, resulting in a relative volatility of unity:
\[ \alpha_{AB} = \frac{\left( \frac{y_{A}}{x_{A}} \right)}{\left( \frac{y_{B}}{x_{B}} \right)} \]
Where the condition for an azeotrope is defined as:
\[ \alpha_{AB} = 1 \quad \text{and} \quad y_{A} = x_{A} \]
| Condition |
Threshold / Regime |
| Pressure Validity |
|Psystem - Patm| ≤ 0.1 bar |
| Azeotropic Criterion |
αAB ≈ 1.0 |
| Composition Range |
0 < xi < 1 |
| Azeotrope Type |
Minimum-boiling (Tazeo < Tpure, A and Tpure, B) |
Worked Example: Azeotrope Identification for Ethanol–Water System
Knowns
- System: Ethanol–Water binary mixture
- Total pressure: \( P = 1.013 \; \text{bar} \) (equivalent to 1 atm)
- Reported azeotropic composition: 95.6 wt% ethanol
- Azeotropic temperature (from VLE data): \( T = 78.15 \; ^{\circ}\text{C} \)
- Molecular weights: \( M_{\text{EtOH}} = 46.07 \; \text{g/mol} \), \( M_{\text{H2O}} = 18.02 \; \text{g/mol} \)
Step-by-Step Calculation
- Convert weight percent to mole fractions.
The weight fraction of ethanol is \( w_{\text{EtOH}} = 0.956 \), and that of water is \( w_{\text{H2O}} = 0.044 \).
Applying the conversion formula \( x_{\text{EtOH}} = \frac{w_{\text{EtOH}}/M_{\text{EtOH}}}{w_{\text{EtOH}}/M_{\text{EtOH}} + w_{\text{H2O}}/M_{\text{H2O}}} \), we obtain the mole fractions from the given data:
\[
x_{\text{EtOH}} = 0.895, \qquad x_{\text{H2O}} = 1 - x_{\text{EtOH}} = 0.105.
\]
- Verify azeotropic condition.
From experimental VLE tables for ethanol–water at 1 atm, at the composition \( x_{\text{EtOH}} = 0.895 \), the vapor composition equals the liquid composition:
\[
y_{\text{EtOH}} = x_{\text{EtOH}} = 0.895.
\]
The relative volatility is defined as
\[
\alpha_{\text{AB}} = \frac{y_{\text{EtOH}} / x_{\text{EtOH}}}{y_{\text{H2O}} / x_{\text{H2O}}}.
\]
Substituting the values gives \( \alpha_{\text{AB}} = 1.000 \), satisfying the azeotropic condition \( y_i = x_i \) and \( \alpha = 1 \).
- Characterize the azeotrope.
The system boils at \( T = 78.15 \; ^{\circ}\text{C} \), which is lower than the normal boiling points of pure ethanol (78.37 °C) and pure water (100 °C) at the same pressure. This indicates a minimum-boiling azeotrope.
Final Answer
The ethanol–water system at \( P = 1.013 \; \text{bar} \) (1 atm) forms a
minimum-boiling azeotrope with the following characteristics:
- Liquid composition: \( x_{\text{EtOH}} = 0.895 \) (95.6 wt% ethanol), \( x_{\text{H2O}} = 0.105 \)
- Vapor composition: \( y_{\text{EtOH}} = 0.895 \)
- Relative volatility: \( \alpha_{\text{AB}} = 1.000 \)
- Azeotropic temperature: \( T = 78.15 \; ^{\circ}\text{C} \)